P.B.Y
03-03-2009, 05:50 AM
hi i need help with my homework i need to graph linear inequalities and my dumb book doesn't explain it well enough here are the problems
y is greater than or equal to 1x+4
-4y>6x-3
y is less than or equal to -2x +8
y>3x-5
-x+2y>6
x+y<4
x-y>7
x+3y is less than or equal to 15
the question is how do i graph these, Wii Points are at stake here, so please help me out!!! Thanks!
matt damon
03-03-2009, 05:57 AM
use a graphing calculator
manny kaltz
03-03-2009, 07:34 AM
All you have to do to solve these questions is:
1. Forget that there are inequality signs and, for now, replace them with equals signs. For example, in the first equation you would have y = x + 4 and in the second equation you would have -4y = 6x - 3.
2. The objective now is to plot these lines on a graph, and it is obviously beneficial for you to convert them in y = ..... eg. the second equation becomes y = -(6x/4) + 3/4.
3. Now this is the step where you should consult your teacher to see what he or she wants you to do. When I first did these types of questions, I was instructed to shade the portion of the graph that voilated the initial inequalities. You can search the proper area by substituting various points into the equation.
So, in the case of the first equation, if you substituted in (x=2,y=4), you would end up with 4>= 6, which is patently not true. Therefore, sub in the area of the graph in which the point (2,4) resides in.
4. Finally, you must deal with the line that you drew in (2). If you have something of the form y>= f(x) or y<= f(x) you keep the line like ________. If the line is of the form y > f(x) or y < f(x) you make the line like --------.
I hope this helps.
Holy serious answer Batman!
jewess crabcake
03-04-2009, 12:40 AM
L-O-friggin-L! I move we have a math forum! And I be a mod... :D. But I like math, and would totally make a math thread which arithmetic-philes would join me?!
Seconded. I want to see where it would go.
Marshall Lee
03-04-2009, 12:50 AM
SKIP IT!!!
discodan
03-04-2009, 02:30 AM
There is no spoon
Marshall Lee
03-04-2009, 03:22 AM
A,E,I,O,U and sometimes Y
StillAlive1364
04-19-2009, 03:38 AM
The cake is a lie!!!
Sciz_Bisket
04-19-2009, 07:11 AM
I approve of the math forum.
Locke_FF36
04-21-2009, 01:11 AM
All you have to do to solve these questions is:
1. Forget that there are inequality signs and, for now, replace them with equals signs. For example, in the first equation you would have y = x + 4 and in the second equation you would have -4y = 6x - 3.
2. The objective now is to plot these lines on a graph, and it is obviously beneficial for you to convert them in y = ..... eg. the second equation becomes y = -(6x/4) + 3/4.
3. Now this is the step where you should consult your teacher to see what he or she wants you to do. When I first did these types of questions, I was instructed to shade the portion of the graph that voilated the initial inequalities. You can search the proper area by substituting various points into the equation.
So, in the case of the first equation, if you substituted in (x=2,y=4), you would end up with 4>= 6, which is patently not true. Therefore, sub in the area of the graph in which the point (2,4) resides in.
4. Finally, you must deal with the line that you drew in (2). If you have something of the form y>= f(x) or y<= f(x) you keep the line like ________. If the line is of the form y > f(x) or y < f(x) you make the line like --------.
I hope this helps.
Good answer cheesedick
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